# Problems on Trains - Aptitude Questions, Shortcuts, Formulas

We cover all the topics and concepts of Aptitude Problems on trains like two trains are moving in opposite directions, calculate train speed, calculate distance, etc.

## Rules on Problem On Trains

Rule 1: When two trains are moving in opposite directions, then relative speed will be the addition of their individual speeds.

Rule 2: When two trains are moving in same direction, then relative speed will be the subtraction of their individual speeds.

Rule 3: On passing a platform by a certain train the net distance traveled is the sum of length of train and the length of platform both.

Rule 4: When a train passes through a pole or person standing, net distance traveled to pass is the length of the train

## Problems on Trains Formulas

• x $km/hr = x \times \frac{5}{18} m/s$
• y $m/s = y\times \frac{18}{5} Km/hr$
• Speed = distance/time
• Velocity = displacement/time
• Time taken by a train x meters long to pass a pole or standing man or a post = Time taken by the train to travel x meters.
• Time taken by a train x meters long to pass an object of length y meters = Time taken by the train to travel (x + y) metres.
• Suppose two trains or two objects are moving in the same direction at v1 m/s and v2 m/s where v 1 > v 2, then their relative speed = (v 1 v 2) m/s
• Suppose two trains or two objects are moving in opposite directions at v 1 m/s and v 2 m/s , then their relative speed = (v 1+ v 2) m/s
• Assume two trains of length x metres and y metres are moving in opposite directions at v 1 m/s and v 2 m/s, Then the time taken by the trains to cross each other = (x+y) / (v 1+v 2) seconds
• Assume two trains of length x metres and y metres are moving in the same direction at at v 1 m/s and v 2 m/s where v 1 > v 2, Then The time taken by the faster train to cross the slower train = (x+y) / (v 1-v 2) seconds.
• Assume that two trains (objects) start from two points P and Q towards each other at the same time and after crossing they take p and q seconds to reach Q and P respectively. Then, A's speed: B's speed = $\sqrt{q} : \sqrt{p}$

## Problems on Trains Aptitude Questions from Previous Year Exams

IBPS questions related to problem on train.

## Problems on Trains Video Lectures

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