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Arithmetic Ability Mock Test

This Mock Test is created questions of Arithmetic Ability, also known as Quantitative Aptitude or Numerical Ability from Previous Year Recruitment Papers by our experts.

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Question 1 of 50

1. Question
1 points
Which number should replace both the question marks (?) in the following equation ?

$\frac{?}{576}=\frac{256}{?}$
- 384
- 398
- 404
- 416
- None of these
Correct

$\frac{?}{576}=\frac{256}{?}$

$\Rightarrow ?^{2}=256\times 576$

$\Rightarrow ?=\sqrt{256\times 576}$

= $16\times 24$

=384

Incorrect

$\frac{?}{576}=\frac{256}{?}$

$\Rightarrow ?^{2}=256\times 576$

$\Rightarrow ?=\sqrt{256\times 576}$

= $16\times 24$

=384
Question 2 of 50

2. Question
1 points
What would be the compound interest obtained on an amount of Rs.20000 at the rate of 15% per annum after 4 yr ?
- Rs.14980.125
- Rs.19680.125
- Rs.16780.125
- Rs.18980.125
- None of these
Correct

C.I. = $20000\left [ (1+\frac{15}{100})^{4} -1\right ]$

= $20000\left [ (\frac{23}{20})^{4} -1\right ]$

= 20000 $\left [ \frac{23\times 23\times 23\times 23-20\times 20\times 20\times 20}{20\times 20\times 20\times 20}\,\,\,\,\,\,\,\,\,\,\right ]$

= 20000 $\left( \frac{279841-160000}{160000}\,\,\,\,\,\,\right)$

= 20000 $\times \frac{119841}{160000}= Rs.14980.125$

Incorrect

C.I. = $20000\left [ (1+\frac{15}{100})^{4} -1\right ]$

= $20000\left [ (\frac{23}{20})^{4} -1\right ]$

= 20000 $\left [ \frac{23\times 23\times 23\times 23-20\times 20\times 20\times 20}{20\times 20\times 20\times 20}\,\,\,\,\,\,\,\,\,\,\right ]$

= 20000 $\left( \frac{279841-160000}{160000}\,\,\,\,\,\,\right)$

= 20000 $\times \frac{119841}{160000}= Rs.14980.125$
Question 3 of 50

3. Question
1 points
What should come in place of question mark (?) in the following number series ?

0 5 18 43 84 145 ?
- 220
- 240
- 260
- 280
- None of these
Correct

Incorrect
Question 4 of 50

4. Question
1 points
If the numerator of a fraction is increased by 200% and the denominator is increased by 350%. The resultant fraction is $\frac{5}{12}$ . What was the original fraction ?
- $\frac{5}{9}$
- $\frac{5}{8}$
- $\frac{7}{12}$
- $\frac{11}{12}$
- None of these
Correct

Suppose original fraction is $\frac{x}{y}$ .

$\therefore \frac{x+\frac{200}{100}x}{y+\frac{350}{100}y}=\frac{5}{12}$

$\Rightarrow \frac{300x}{100}\times \frac{100}{450y}=\frac{5}{12}$

$\Rightarrow \frac{300x}{450y}=\frac{5}{12}$

$\Rightarrow \frac{2x}{3y}=\frac{5}{12}$

$\Rightarrow \frac{x}{y}=\frac{5}{12}\times \frac{3}{2}$

$\Rightarrow \frac{x}{y}=\frac{5}{8}$

Short cut

$\frac{x+2x}{y+3.5y}=\frac{5}{12}$

$\frac{3x}{4.5y}=\frac{5}{12}$

$\frac{x}{y}=\frac{5\times 4.5}{3\times 12}=\frac{5}{8}$

Incorrect

Suppose original fraction is $\frac{x}{y}$ .

$\therefore \frac{x+\frac{200}{100}x}{y+\frac{350}{100}y}=\frac{5}{12}$

$\Rightarrow \frac{300x}{100}\times \frac{100}{450y}=\frac{5}{12}$

$\Rightarrow \frac{300x}{450y}=\frac{5}{12}$

$\Rightarrow \frac{2x}{3y}=\frac{5}{12}$

$\Rightarrow \frac{x}{y}=\frac{5}{12}\times \frac{3}{2}$

$\Rightarrow \frac{x}{y}=\frac{5}{8}$

Short cut

$\frac{x+2x}{y+3.5y}=\frac{5}{12}$

$\frac{3x}{4.5y}=\frac{5}{12}$

$\frac{x}{y}=\frac{5\times 4.5}{3\times 12}=\frac{5}{8}$
Question 5 of 50

5. Question
1 points
If 3Y+9X=54 and $\frac{28x}{13y}=\frac{140}{39}$ then what is the value of Y-X ?
- -1
- -2
- 2
- 1
- None of these
Correct

3Y+9X=54

$\frac{28x}{13y}=\frac{140}{39}$

1820Y-1092X=0

From equations (i) and (ii),

X=5, Y=3

$\therefore$ Y-X= 3-5 = - 2

Incorrect

3Y+9X=54

$\frac{28x}{13y}=\frac{140}{39}$

1820Y-1092X=0

From equations (i) and (ii),

X=5, Y=3

$\therefore$ Y-X= 3-5 = - 2
Question 6 of 50

6. Question
1 points
The difference between the $\frac{3}{4}th$ of $\frac{4}{5}th$ of a number and $\frac{1}{6}th$ of $\frac{2}{5}th$ of the same number is 648. What is the number ?
- 1110
- 1215
- 1325
- 1440
- None of these
Correct

Suppose number is x,

$\therefore x\times \frac{4}{5}\times \frac{3}{4}-x\times \frac{2}{5}\times \frac{1}{6}=648$

$\frac{12x}{20}-\frac{2x}{30}=648$

$\Rightarrow \frac{36x-4x}{60}=648$

$\Rightarrow \frac{32x}{60}=648$

$\Rightarrow \frac{648\times 60}{32}=81\times 35$

$\Rightarrow$ x = 1215

Incorrect

Suppose number is x,

$\therefore x\times \frac{4}{5}\times \frac{3}{4}-x\times \frac{2}{5}\times \frac{1}{6}=648$

$\frac{12x}{20}-\frac{2x}{30}=648$

$\Rightarrow \frac{36x-4x}{60}=648$

$\Rightarrow \frac{32x}{60}=648$

$\Rightarrow \frac{648\times 60}{32}=81\times 35$

$\Rightarrow$ x = 1215
Question 7 of 50

7. Question
1 points
On a school's Annual Day sweets were to be equally distributed amongst 112 children. But on that particular day, 32 children were absent. Thus the remaining children got 6 extra sweets. How many sweets was each child originally to get ?
- 24
- 18
- 15
- Cannot be determined
- None of these
Correct

Suppose each child got x sweets.

$\therefore 112\times x=(112-32)\times (x+6)$

$112 x=80\times (x+6)$

112 x=80 x + 480

112 x - 80 x = 480

32 x = 480

x = 15

Incorrect

Suppose each child got x sweets.

$\therefore 112\times x=(112-32)\times (x+6)$

$112 x=80\times (x+6)$

112 x=80 x + 480

112 x - 80 x = 480

32 x = 480

x = 15
Question 8 of 50

8. Question
1 points
If $3\frac{4}{5}$ is subtracted from $6\frac{3}{5}$ and difference is multiplied by 355 then what will be the final number ?
- 1004
- 884
- 774
- 994
- None of these
Correct

$\left ( 6\frac{3}{5}-3\frac{4}{5} \right )\times 355=\left ( \frac{33}{5}-\frac{19}{5} \right )\times 355$

= $\left ( \frac{33-19}{5} \right )\times 355$

= $\frac{14\times 355}{5}$ =994

Incorrect

$\left ( 6\frac{3}{5}-3\frac{4}{5} \right )\times 355=\left ( \frac{33}{5}-\frac{19}{5} \right )\times 355$

= $\left ( \frac{33-19}{5} \right )\times 355$

= $\frac{14\times 355}{5}$ =994
Question 9 of 50

9. Question
1 points
An order was placed for supply of carpet of breadth 3m, the length of carpet was 1.44 times of breadth. Subsequently the breadth and length were increased by 25% and 40% respectively. At the rate of Rs.45 per square metre, What would be the increase in the cost of the carpet ?
- Rs.1020.6
- Rs.398.8
- Rs.437.4
- Rs.583.2
- None of these
Correct

Breadth of carpet = 3 m

Length of carpet = $3\times 1.44=432 m$

Original cost of carpet

= $3\times 4.32\times 45$

=Rs. 583.20

Cost of carpet after increasing of length an breadth

= $3\times \frac{125}{100}\times 4.32\times \frac{140}{100}\times 45$

= $15\times 1.08\times 7\times 9 = Rs.1020.60$

$\therefore$ Increase (Difference) = 1020.60 - 583.20

= Rs. 437.40

Incorrect

Breadth of carpet = 3 m

Length of carpet = $3\times 1.44=432 m$

Original cost of carpet

= $3\times 4.32\times 45$

=Rs. 583.20

Cost of carpet after increasing of length an breadth

= $3\times \frac{125}{100}\times 4.32\times \frac{140}{100}\times 45$

= $15\times 1.08\times 7\times 9 = Rs.1020.60$

$\therefore$ Increase (Difference) = 1020.60 - 583.20

= Rs. 437.40
Question 10 of 50

10. Question
1 points
The length of a rectangular plot is thrice its breadth. If the area of the rectangular plot is 7803 sq.m, What is the breadth of the rectangular plot ?
- 51 m
- 153 m
- 104 m
- 88 m
- None of these
Correct

Suppose the breadth of the plot is x m and length is 3 x m.

Area of the rectangular plot

= $3 x\times x = 7803$

$\Rightarrow 3 x^{2}=7803$

$\therefore x = \sqrt{\frac{7803}{3}}=\sqrt{2601}$

x = 51 m.

Incorrect

Suppose the breadth of the plot is x m and length is 3 x m.

Area of the rectangular plot

= $3 x\times x = 7803$

$\Rightarrow 3 x^{2}=7803$

$\therefore x = \sqrt{\frac{7803}{3}}=\sqrt{2601}$

x = 51 m.
Question 11 of 50

11. Question
1 points
Ratio of Rani's and Komal's age is 3 : 5 respectively, Ratio of Komal's and Pooja's age is 2 : 3 respectively. If Rani is two-fifth Pooja's age. What is Rani's age ?
- 10 yr
- 15 yr
- 24 yr
- Cannot be determined
- None of the above
Correct

Incorrect
Question 12 of 50

12. Question
1 points
In a mixture of milk and water the proportion of water by weight was 75%. If in the 60 gm mixture, 15 gm water was added, What would be the percentage of water ?
- 75%
- 88%
- 90%
- 100%
- None of these
Correct

Weight of water in the mixture of 60 g water

= $60\times \frac{75}{100}$ = 45 g

Weight of water in the mixture of 45 g water

= 45 + 15 = 60 g

$\therefore Percentage of water = \frac{60\times 100}{75}$ = 80%

Incorrect

Weight of water in the mixture of 60 g water

= $60\times \frac{75}{100}$ = 45 g

Weight of water in the mixture of 45 g water

= 45 + 15 = 60 g

$\therefore Percentage of water = \frac{60\times 100}{75}$ = 80%
Question 13 of 50

13. Question
1 points
The sum of five numbers is 290. The average of the first two numbers is 48.5 and the average of last two numbers is 53.5. What is the third number ?
- 72
- 84
- 96
- 108
- None of these
Correct

Average of first two numbers = 48.5

Average of last two numbers = 53.5

Sum of five numbers = 290

Third number = x

$\therefore 2\times (48.5)+x+2\times (53.5) = 290$

97 + x + 107 = 290

x = 290 - 204

x = 86

Incorrect

Average of first two numbers = 48.5

Average of last two numbers = 53.5

Sum of five numbers = 290

Third number = x

$\therefore 2\times (48.5)+x+2\times (53.5) = 290$

97 + x + 107 = 290

x = 290 - 204

x = 86
Question 14 of 50

14. Question
1 points
In how many different ways can the letters of the word 'SMART' be arranged ?
- 125
- 60
- 180
- 200
- None of these
Correct

There are 5 letters in the word SMART.

So, the required number of ways to arrange

= $^{5}P_{5}$ = 5 !

= $5\times 4\times 3\times 2\times 1$

= 120

Incorrect

There are 5 letters in the word SMART.

So, the required number of ways to arrange

= $^{5}P_{5}$ = 5 !

= $5\times 4\times 3\times 2\times 1$

= 120
Question 15 of 50

15. Question
1 points
A sum of Rs. 2236 is divided among A, B and C such that A receive 25% more than C and C receive 25% less than B. What is A's share in the amount ?
- Rs.460
- Rs.890
- Rs.780
- Rs.1280
- None of these
Correct

Suppose B got Rs. x,

Amount to C = x - $x\times \frac{25}{100}$

= $\frac{100x-25x}{100}$

= $\frac{75x}{100}= Rs.\frac{3x}{4}$

So, the amount to A = $\frac{3x}{4}\times \frac{125}{100}= \frac{15x}{16}$

A : B : C : = $\frac{15x}{16}: x : \frac{3x}{4}$

= 15 x : 16 x : 12 x

Sum of the ratio = 15 x + 16 x + 12 x = 43 x

$\therefore Share of A =\frac{2236\times 15x}{43x}$

= Rs.780.

Incorrect

Suppose B got Rs. x,

Amount to C = x - $x\times \frac{25}{100}$

= $\frac{100x-25x}{100}$

= $\frac{75x}{100}= Rs.\frac{3x}{4}$

So, the amount to A = $\frac{3x}{4}\times \frac{125}{100}= \frac{15x}{16}$

A : B : C : = $\frac{15x}{16}: x : \frac{3x}{4}$

= 15 x : 16 x : 12 x

Sum of the ratio = 15 x + 16 x + 12 x = 43 x

$\therefore Share of A =\frac{2236\times 15x}{43x}$

= Rs.780.
Question 16 of 50

16. Question
1 points
The average weight of a group of 53 girls was calculated as 58 kg. It was later discovered that weight of one of the girls was read as 65 kg. What is the actual average weight of the group of 53 girls ? (rounded off to two digits after decimal)
- 58.62
- 58.37
- 57.37
- 57.62
- None of these
Correct

Loss in weight = 65 - 45 =20 kg

Loss in average weight = $\frac{20}{53}$ = 0.38 kg

Original average weight = 58 - 0.38

= 57.62 kg

Incorrect

Loss in weight = 65 - 45 =20 kg

Loss in average weight = $\frac{20}{53}$ = 0.38 kg

Original average weight = 58 - 0.38

= 57.62 kg
Question 17 of 50

17. Question
1 points
What should come in place of question mark (?) in the following number series ?

10 17 48 165 688 3475 ?
- 27584
- 25670
- 21369
- 20892
- None of these
Correct

Incorrect
Question 18 of 50

18. Question
1 points
What should come in place of question mark (?) in the following number series ?

1 3 24 360 8640 302400 ?
- 14525100
- 154152000
- 14515200
- 15425100
- None of these
Correct

Incorrect
Question 19 of 50

19. Question
1 points
What should come in place of question mark (?) in the following number series ?

12 14 32 102 416 2090 ?
- 15522
- 12552
- 13525
- 17552
- None of these
Correct

Incorrect
Question 20 of 50

20. Question
1 points
What should come in place of question mark (?) in the following number series ?

10 15 15 12.5 9.375 6.5625 ?
- 4.375
- 3.2375
- 4.6275
- 3.575
- None of these
Correct

Incorrect
Question 21 of 50

21. Question
1 points
Study the following pie-charts carefully to answer the questions that follow.

What is the total number of boys enrolled in Management and IT together ?
- 1050
- 810
- 1120
- 980
- None of these
Correct

Number of boys in management

= $3500\times \frac{16}{100}-1500\times \frac{12}{100}$

= 560 - 180 = 380

Number of boys in IT

= $3500\times \frac{20}{100}-1500\times \frac{18}{100}$

= 700 - 270 = 430

$\therefore$ Total number of boys in both = 380 + 430 = 810

Incorrect

Number of boys in management

= $3500\times \frac{16}{100}-1500\times \frac{12}{100}$

= 560 - 180 = 380

Number of boys in IT

= $3500\times \frac{20}{100}-1500\times \frac{18}{100}$

= 700 - 270 = 430

$\therefore$ Total number of boys in both = 380 + 430 = 810
Question 22 of 50

22. Question
1 points
Study the following pie-charts carefully to answer the questions that follow.

What is the respective ratio of number of girls enrolled Arts to the number of boys enrolled in Science ?
- 14 : 23
- 2 : 3
- 114 : 121
- 53 : 65
- None of these
Correct

Number of girls in Art = $1500\times \frac{38}{100}=570$

Number of boys in Science = $3500\times \frac{22}{100}-1500\times \frac{11}{100}$

= 770 - 165 = 605

$\therefore$ Required ratio = 570 : 605 = 114 : 121

Incorrect

Number of girls in Art = $1500\times \frac{38}{100}=570$

Number of boys in Science = $3500\times \frac{22}{100}-1500\times \frac{11}{100}$

= 770 - 165 = 605

$\therefore$ Required ratio = 570 : 605 = 114 : 121
Question 23 of 50

23. Question
1 points
Study the following pie-charts carefully to answer the questions that follow.

What is the total number of girls enrolled in Science and Commerce together ?
- 450
- 495
- 345
- 480
- None of these
Correct

Total number of girls in Science and Commerce together

= $1500\times \frac{(21+11)}{100}= 480$

Incorrect

Total number of girls in Science and Commerce together

= $1500\times \frac{(21+11)}{100}= 480$
Question 24 of 50

24. Question
1 points
Study the following pie-charts carefully to answer the questions that follow.

If 20% of the girls enrolled in Science change their stream to Management then what will be the new number of Management students altogether ?
- 593
- 733
- 453
- 1003
- None of these
Correct

Number of girls in Science= $1500\times \frac{11}{100}= 165$

20% girls from Science merged into Management then the number of students

= $3500\times \frac{16}{100}+165\times \frac{20}{100}$

=560 + 33 = 593

Incorrect

Number of girls in Science= $1500\times \frac{11}{100}= 165$

20% girls from Science merged into Management then the number of students

= $3500\times \frac{16}{100}+165\times \frac{20}{100}$

=560 + 33 = 593
Question 25 of 50

25. Question
1 points
Study the following pie-charts carefully to answer the questions that follow.

Number of girls enrolled in Art, Science and Commerce forms. What per cent of total number of students in the college ?
- 25
- 40
- 60
- 75
- None of these
Correct

Total number of girls in Arts, Science and Commerce together

= $1500\times \frac{(38+11+21)}{100}= 1050$

Required percentage= $\frac{1050\times 100}{3500}$ = 30%

Incorrect

Total number of girls in Arts, Science and Commerce together

= $1500\times \frac{(38+11+21)}{100}= 1050$

Required percentage= $\frac{1050\times 100}{3500}$ = 30%
Question 26 of 50

26. Question
1 points
study the following graph carefully to answer the questions that follow.

What is the respective ratio of the total production of companies D and E to the total sale of the same companies ?
- 28 : 15
- 9 : 5
- 15 : 11
- 2 : 3
- None of the above
Correct

Total production of Company D and E

= 850 + 550 = 1400

Total sales of Company D and E

= 450 + 300 = 750

Required ratio = 1400 : 750 = 28 : 15

Incorrect

Total production of Company D and E

= 850 + 550 = 1400

Total sales of Company D and E

= 450 + 300 = 750

Required ratio = 1400 : 750 = 28 : 15
Question 27 of 50

27. Question
1 points
study the following graph carefully to answer the questions that follow.

What is the average number of units produced by all the companies together ?
- 675
- 650
- 625
- 600
- None of the above
Correct

Average production of games by all the companies together

= $\frac{900+700+300+850+550+660}{6}$

= $\frac{3900}{6}$

= 650

Incorrect

Average production of games by all the companies together

= $\frac{900+700+300+850+550+660}{6}$

= $\frac{3900}{6}$

= 650
Question 28 of 50

28. Question
1 points
study the following graph carefully to answer the questions that follow.

Which company had the highest percentage of sale with respect to its production ?
- D
- B
- E
- A
- None of the above
Correct

Percentage of production to sales of Company A= $\frac{650\times 100}{900}= 72.22$ %

Percentage of production to sale of Company B= $\frac{300\times 100}{700}= 42.86$ %

Percentage of production to sale of Company C= $\frac{150\times 100}{300}= 50$ %

Percentage of production to sale of Company D= $\frac{450\times 100}{850}= 52.94$ %

Percentage of Production to sale of Company E= $\frac{300\times 100}{550}= 54.55$ %

Percentage of Production to sale of Company F= $\frac{400\times 100}{600}= 66.67$ %

So, maximum sales percentage was of Company A.

Incorrect

Percentage of production to sales of Company A= $\frac{650\times 100}{900}= 72.22$ %

Percentage of production to sale of Company B= $\frac{300\times 100}{700}= 42.86$ %

Percentage of production to sale of Company C= $\frac{150\times 100}{300}= 50$ %

Percentage of production to sale of Company D= $\frac{450\times 100}{850}= 52.94$ %

Percentage of Production to sale of Company E= $\frac{300\times 100}{550}= 54.55$ %

Percentage of Production to sale of Company F= $\frac{400\times 100}{600}= 66.67$ %

So, maximum sales percentage was of Company A.
Question 29 of 50

29. Question
1 points
study the following graph carefully to answer the questions that follow.

What is the average number of units sold by the all the companies together ?
- 360
- 390
- 375
- 410
- None of these
Correct

Average sales of gems by all the Companies together

= $\frac{650+300+150+450+300+400}{6}$

= $\frac{2250}{6}$

=375.

Incorrect

Average sales of gems by all the Companies together

= $\frac{650+300+150+450+300+400}{6}$

= $\frac{2250}{6}$

=375.
Question 30 of 50

30. Question
1 points
study the following graph carefully to answer the questions that follow.

The total units sold by these companies A, B and C together is approximately what per cent of the total units produced of these companies ?
- 62
- 50
- 76
- 84
- 58
Correct

Sales of gems by Companies A, B and C together

=650 + 300 + 150 = 1100

Total production by Companies A, B and C together

=900 + 700 + 300 =1900

Required percentage = $\frac{1100\times 100}{1900}$

=57.89 ≈ 58 (Approx.)

Incorrect

Sales of gems by Companies A, B and C together

=650 + 300 + 150 = 1100

Total production by Companies A, B and C together

=900 + 700 + 300 =1900

Required percentage = $\frac{1100\times 100}{1900}$

=57.89 ≈ 58 (Approx.)
Question 31 of 50

31. Question
1 points
Study the table carefully to answer the questions that follow.

What is the difference in the total number of workers working in various months from factory A and the total number of workers working in various months from factory E ?
- 3540
- 3940
- 3290
- 4230
- None of these
Correct

Total number of workers in factory A over the months

= $(65+78+42+51+60+63.5)\times 100$

=35950

Total number of workers in factory E over the months

= $(83+74+70.3+66+56.9+44.7)\times 100$

=39490

Required difference= 39490 - 35950

= 3540

Incorrect

Total number of workers in factory A over the months

= $(65+78+42+51+60+63.5)\times 100$

=35950

Total number of workers in factory E over the months

= $(83+74+70.3+66+56.9+44.7)\times 100$

=39490

Required difference= 39490 - 35950

= 3540
Question 32 of 50

32. Question
1 points
Study the table carefully to answer the questions that follow.

The total number of workers from factory B is approximately what per cent of the total number of workers from factory D ?
- 56
- 65
- 76
- 84
- 92
Correct

Total number of workers in factory B

= (41.2+30+65+72.8+68.2++52.5)

=329.7

Total number of workers in factory D

=63.5+60+76+21.8+80.2+57

=358.5

Required percentage= $\frac{329.7\times 100}{358.5}$ = 91.97

≈ 92 (Approx.)

Incorrect

Total number of workers in factory B

= (41.2+30+65+72.8+68.2++52.5)

=329.7

Total number of workers in factory D

=63.5+60+76+21.8+80.2+57

=358.5

Required percentage= $\frac{329.7\times 100}{358.5}$ = 91.97

≈ 92 (Approx.)
Question 33 of 50

33. Question
1 points
Study the table carefully to answer the questions that follow.

What is the average number of workers working in various months from factory C ?
- 70.55
- 7055
- 6780
- 67.80
- None of these
Correct

Average number of workers in factory C

= $\frac{7240+6100+7160+8350+6160+7320}{6}$

= $\frac{42330}{6}$ = 7055

Incorrect

Average number of workers in factory C

= $\frac{7240+6100+7160+8350+6160+7320}{6}$

= $\frac{42330}{6}$ = 7055
Question 34 of 50

34. Question
1 points
Study the table carefully to answer the questions that follow.

What is the respective of the total number of workers from factories B and C working in the month of March and the total number of workers working in the same month from factories A and D ?
- 5 : 6
- 238 : 345
- 59 : 69
- 683 : 590
- None of these
Correct

Total number of workers in March in factories B and C = 6500+7160 = 13660

Total number of workers in March in factories A and D = 4200+7600 = 11800

Required ratio = 13660 : 11800 = 683 : 590

Incorrect

Total number of workers in March in factories B and C = 6500+7160 = 13660

Total number of workers in March in factories A and D = 4200+7600 = 11800

Required ratio = 13660 : 11800 = 683 : 590
Question 35 of 50

35. Question
1 points
Study the table carefully to answer the questions that follow.

What is the total of the average of number of workers working in the months of January from all the factories and the average of number of workers working in the month of April from all the factories ?
- 10098
- 11290
- 12404
- 13516
- None of these
Correct

Average number of workers in January

= $\frac{6500+4120+7240+6350+8300}{5}$

= $\frac{32510}{5}$

=6502

Average number of workers in March

= $\frac{5100+7280+8350+2180+6600}{5}$

= $\frac{29510}{5}$

=5902

Total = 6502 + 5902 =12404

Incorrect

Average number of workers in January

= $\frac{6500+4120+7240+6350+8300}{5}$

= $\frac{32510}{5}$

=6502

Average number of workers in March

= $\frac{5100+7280+8350+2180+6600}{5}$

= $\frac{29510}{5}$

=5902

Total = 6502 + 5902 =12404
Question 36 of 50

36. Question
1 points
Study the information carefully to answer the following questions.

A management institute offers MBA with specialization in Marketing. Finance and HR. Among the total number of students in the institute 45% are girls. Number of boys studying Marketing is 30% of the total number of boys in the institute which is 297.40% of the girls are studying HR. Number of boys and girls studying Marketing are in the ratio of 3 : 2. 50% of boys are studying Finance.

How many girls are studying Finance ?
- 288
- 198
- 324
- 495
- None of these
Correct

Total number of boys studying Marketing = 297

$\therefore$ Total number of boys in the institution= $\frac{297\times 100}{30}$ = 990

So, the total number of girls = $\frac{45}{55}\times 990$ = 810

Total number of girls studying HR= $810\times \frac{40}{100}$ = 324

Total number of girls studying Marketing = $297\times \frac{2}{3}$ =198

Total number of boys studying Finance= $\frac{1}{2}\times 990$ = 495

Total number of boys studying HR=990 - 297 - 495 = 198

Total number of girls studying Finance= 810 -324 - 198

= 288

Incorrect

Total number of boys studying Marketing = 297

$\therefore$ Total number of boys in the institution= $\frac{297\times 100}{30}$ = 990

So, the total number of girls = $\frac{45}{55}\times 990$ = 810

Total number of girls studying HR= $810\times \frac{40}{100}$ = 324

Total number of girls studying Marketing = $297\times \frac{2}{3}$ =198

Total number of boys studying Finance= $\frac{1}{2}\times 990$ = 495

Total number of boys studying HR=990 - 297 - 495 = 198

Total number of girls studying Finance= 810 -324 - 198

= 288
Question 37 of 50

37. Question
1 points
Study the information carefully to answer the following questions.

A management institute offers MBA with specialization in Marketing. Finance and HR. Among the total number of students in the institute 45% are girls. Number of boys studying Marketing is 30% of the total number of boys in the institute which is 297.40% of the girls are studying HR. Number of boys and girls studying Marketing are in the ratio of 3 : 2. 50% of boys are studying Finance.

Number of girls studying Marketing is what per cent of the number of boys studying Finance ?
- 20
- 35
- 50
- 65
- None of these
Correct

Total number of boys studying Marketing = 297

$\therefore$ Total number of boys in the institution= $\frac{297\times 100}{30}$ = 990

So, the total number of girls = $\frac{45}{55}\times 990$ = 810

Total number of girls studying HR= $810\times \frac{40}{100}$ = 324

Total number of girls studying Marketing = $297\times \frac{2}{3}$ =198

Total number of boys studying Finance= $\frac{1}{2}\times 990$ = 495

Total number of boys studying HR=990 - 297 - 495 = 198

Required percentage = $\frac{198}{495}\times 100$ =40

Incorrect

Total number of boys studying Marketing = 297

$\therefore$ Total number of boys in the institution= $\frac{297\times 100}{30}$ = 990

So, the total number of girls = $\frac{45}{55}\times 990$ = 810

Total number of girls studying HR= $810\times \frac{40}{100}$ = 324

Total number of girls studying Marketing = $297\times \frac{2}{3}$ =198

Total number of boys studying Finance= $\frac{1}{2}\times 990$ = 495

Total number of boys studying HR=990 - 297 - 495 = 198

Required percentage = $\frac{198}{495}\times 100$ =40
Question 38 of 50

38. Question
1 points
Study the information carefully to answer the following questions.

A management institute offers MBA with specialization in Marketing. Finance and HR. Among the total number of students in the institute 45% are girls. Number of boys studying Marketing is 30% of the total number of boys in the institute which is 297.40% of the girls are studying HR. Number of boys and girls studying Marketing are in the ratio of 3 : 2. 50% of boys are studying Finance.

Number of boys studying Finance is what percent of the total number of students in the institution ?
- 33.33
- 27.5
- 47.8
- 13.98
- None of these
Correct

Total number of boys studying Marketing = 297

$\therefore$ Total number of boys in the institution= $\frac{297\times 100}{30}$ = 990

So, the total number of girls = $\frac{45}{55}\times 990$ = 810

Total number of girls studying HR= $810\times \frac{40}{100}$ = 324

Total number of girls studying Marketing = $297\times \frac{2}{3}$ =198

Total number of boys studying Finance= $\frac{1}{2}\times 990$ = 495

Total number of boys studying HR=990 - 297 - 495 = 198

Total number of students in the institution

= 990 + 810 = 1800

Required percentage = $\frac{495}{1800}\times 100$

= 27.50

Incorrect

Total number of boys studying Marketing = 297

$\therefore$ Total number of boys in the institution= $\frac{297\times 100}{30}$ = 990

So, the total number of girls = $\frac{45}{55}\times 990$ = 810

Total number of girls studying HR= $810\times \frac{40}{100}$ = 324

Total number of girls studying Marketing = $297\times \frac{2}{3}$ =198

Total number of boys studying Finance= $\frac{1}{2}\times 990$ = 495

Total number of boys studying HR=990 - 297 - 495 = 198

Total number of students in the institution

= 990 + 810 = 1800

Required percentage = $\frac{495}{1800}\times 100$

= 27.50
Question 39 of 50

39. Question
1 points
Study the information carefully to answer the following questions.

A management institute offers MBA with specialization in Marketing. Finance and HR. Among the total number of students in the institute 45% are girls. Number of boys studying Marketing is 30% of the total number of boys in the institute which is 297.40% of the girls are studying HR. Number of boys and girls studying Marketing are in the ratio of 3 : 2. 50% of boys are studying Finance.

What is the respective ratio between number of boys and girls studying HR ?
- 5 : 9
- 15 : 34
- 99 : 161
- 11 : 18
- None of the above
Correct

Total number of boys studying Marketing = 297

$\therefore$ Total number of boys in the institution= $\frac{297\times 100}{30}$ = 990

So, the total number of girls = $\frac{45}{55}\times 990$ = 810

Total number of girls studying HR= $810\times \frac{40}{100}$ = 324

Total number of girls studying Marketing = $297\times \frac{2}{3}$ =198

Total number of boys studying Finance= $\frac{1}{2}\times 990$ = 495

Total number of boys studying HR=990 - 297 - 495 = 198

Total number of boys studying HR = 198

Total number of girls studying HR = 324

Required ratio = 198 : 324 = 11 : 18

Incorrect

Total number of boys studying Marketing = 297

$\therefore$ Total number of boys in the institution= $\frac{297\times 100}{30}$ = 990

So, the total number of girls = $\frac{45}{55}\times 990$ = 810

Total number of girls studying HR= $810\times \frac{40}{100}$ = 324

Total number of girls studying Marketing = $297\times \frac{2}{3}$ =198

Total number of boys studying Finance= $\frac{1}{2}\times 990$ = 495

Total number of boys studying HR=990 - 297 - 495 = 198

Total number of boys studying HR = 198

Total number of girls studying HR = 324

Required ratio = 198 : 324 = 11 : 18
Question 40 of 50

40. Question
1 points
Study the information carefully to answer the following questions.

A management institute offers MBA with specialization in Marketing. Finance and HR. Among the total number of students in the institute 45% are girls. Number of boys studying Marketing is 30% of the total number of boys in the institute which is 297.40% of the girls are studying HR. Number of boys and girls studying Marketing are in the ratio of 3 : 2. 50% of boys are studying Finance.

What is the total number of students in the institute ?
- 1000
- 1500
- 1800
- 900
- None of these
Correct

Total number of boys studying Marketing = 297

$\therefore$ Total number of boys in the institution= $\frac{297\times 100}{30}$ = 990

So, the total number of girls = $\frac{45}{55}\times 990$ = 810

Total number of girls studying HR= $810\times \frac{40}{100}$ = 324

Total number of girls studying Marketing = $297\times \frac{2}{3}$ =198

Total number of boys studying Finance= $\frac{1}{2}\times 990$ = 495

Total number of boys studying HR=990 - 297 - 495 = 198

Total number of students in the institution = 990 + 810 = 1800

Incorrect

Total number of boys studying Marketing = 297

$\therefore$ Total number of boys in the institution= $\frac{297\times 100}{30}$ = 990

So, the total number of girls = $\frac{45}{55}\times 990$ = 810

Total number of girls studying HR= $810\times \frac{40}{100}$ = 324

Total number of girls studying Marketing = $297\times \frac{2}{3}$ =198

Total number of boys studying Finance= $\frac{1}{2}\times 990$ = 495

Total number of boys studying HR=990 - 297 - 495 = 198

Total number of students in the institution = 990 + 810 = 1800
Question 41 of 50

41. Question
1 points
Each question below is followed by two statements A and B. You are to determine whether the data given in the statement is sufficient for answering the question. You should use the data and your knowledge of Mathematics to choose between the possible answers.

What is the speed of the car ?

A. The car covers a distance of 135 km in 3 h.

B. The car covers a distance of 270 km in 6 h.
- if the statement A alone is sufficient to answer the question. but the statement B alone is not sufficient.
- if the statement B alone is sufficient to answer the question. but the statement A alone is not sufficient.
- if both statement A and B together are needed to answer the question.
- if either the statement A alone or statement B alone is sufficient to answer the question.
- if you cannot get the answer the question from the statement A and B together. but need even more data.
Correct

From statement (A)

Speed of the car = $\frac{135}{3}$ = 45 km/h.

From statement (B)

Speed of the car = $\frac{270}{6}$ = 45 km/h.

Incorrect

From statement (A)

Speed of the car = $\frac{135}{3}$ = 45 km/h.

From statement (B)

Speed of the car = $\frac{270}{6}$ = 45 km/h.
Question 42 of 50

42. Question
1 points
Each question below is followed by two statements A and B. You are to determine whether the data given in the statement is sufficient for answering the question. You should use the data and your knowledge of Mathematics to choose between the possible answers.

What is the value of the two digit number ?

A. The product of the digit is 72 and the difference between the digit is 1.

B. The digit at the unit place is greater than the other.
- if the statement A alone is sufficient to answer the question. but the statement B alone is not sufficient.
- if the statement B alone is sufficient to answer the question. but the statement A alone is not sufficient.
- if both statement A and B together are needed to answer the question.
- if either the statement A alone or statement B alone is sufficient to answer the question.
- if you cannot get the answer the question from the statement A and B together. but need even more data.
Correct

x y=72 and x - y =1 ............(i)

$(x+y)^{2}=(x-y)^{2}+ 4x y$

= $(1)^{2}+4\times 72 = 289$

$\therefore$ x + y =17 ....(ii)

From eq.(i) and (ii)

Unit digit = 9

Number = 10 y +x = $10\times 8+9 =89$

Incorrect

x y=72 and x - y =1 ............(i)

$(x+y)^{2}=(x-y)^{2}+ 4x y$

= $(1)^{2}+4\times 72 = 289$

$\therefore$ x + y =17 ....(ii)

From eq.(i) and (ii)

Unit digit = 9

Number = 10 y +x = $10\times 8+9 =89$
Question 43 of 50

43. Question
1 points
Each question below is followed by two statements A and B. You are to determine whether the data given in the statement is sufficient for answering the question. You should use the data and your knowledge of Mathematics to choose between the possible answers.

What is the ratio of the total number of girls to the total number of boys in a college ?

A. There are 2500 students in the college out of which 40% are boys.

B. The ratio of the total number of boys to the total number of girls in the last year was 5 : 6.
- if the statement A alone is sufficient to answer the question. but the statement B alone is not sufficient.
- if the statement B alone is sufficient to answer the question. but the statement A alone is not sufficient.
- if both statement A and B together are needed to answer the question.
- if either the statement A alone or statement B alone is sufficient to answer the question.
- if you cannot get the answer the question from the statement A and B together. but need even more data.
Correct

From statement (A).

$2500\times \frac{40}{100}$ = 1000 boys

Girls = 2500 - 1000 = 1500

Required ratio = 1500 : 1000 = 3 : 2

Incorrect

From statement (A).

$2500\times \frac{40}{100}$ = 1000 boys

Girls = 2500 - 1000 = 1500

Required ratio = 1500 : 1000 = 3 : 2
Question 44 of 50

44. Question
1 points
Each question below is followed by two statements A and B. You are to determine whether the data given in the statement is sufficient for answering the question. You should use the data and your knowledge of Mathematics to choose between the possible answers.

What is the number ?

A. 75% of the number is three-month of that number.

B. One-third of that number is less by 27 of the half on that number.
- if the statement A alone is sufficient to answer the question. but the statement B alone is not sufficient.
- if the statement B alone is sufficient to answer the question. but the statement A alone is not sufficient.
- if both statement A and B together are needed to answer the question.
- if either the statement A alone or statement B alone is sufficient to answer the question.
- if you cannot get the answer the question from the statement A and B together. but need even more data.
Correct

From statement (B), $\frac{x}{3}+27 = \frac{x}{2}$

$\Rightarrow \frac{x}{2}- \frac{x}{3}= 27$

$\Rightarrow x = 27\times 6$

$\Rightarrow$ x = 162

Incorrect

From statement (B), $\frac{x}{3}+27 = \frac{x}{2}$

$\Rightarrow \frac{x}{2}- \frac{x}{3}= 27$

$\Rightarrow x = 27\times 6$

$\Rightarrow$ x = 162
Question 45 of 50

45. Question
1 points
Each question below is followed by two statements A and B. You are to determine whether the data given in the statement is sufficient for answering the question. You should use the data and your knowledge of Mathematics to choose between the possible answers.

What is Deepali's age ?

A. Deepali is two times younger to Nisha.

B. Supriya is twice the age of Nisha.
- if the statement A alone is sufficient to answer the question. but the statement B alone is not sufficient.
- if the statement B alone is sufficient to answer the question. but the statement A alone is not sufficient.
- if both statement A and B together are needed to answer the question.
- if either the statement A alone or statement B alone is sufficient to answer the question.
- if you cannot get the answer the question from the statement A and B together. but need even more data.
Correct

More data required.

Incorrect

More data required.
Question 46 of 50

46. Question
1 points
Study the table carefully to answer the questions that follow.

What is the difference between the number of students appeared but not qualified in the exam from Institute B in the year 2004 and the number of students appeared but not qualified in the exam from the same Institute in the year 2006 ?
- 187
- 88
- 275
- 373
- None of the above
Correct

Number of failed students from institution B in the year 2004 = 1654 - 1566 = 88

Number of failed students from institution B in the year 2006 = 1440 - 1165 = 275

Required difference = 275 - 88 = 187

Incorrect

Number of failed students from institution B in the year 2004 = 1654 - 1566 = 88

Number of failed students from institution B in the year 2006 = 1440 - 1165 = 275

Required difference = 275 - 88 = 187
Question 47 of 50

47. Question
1 points
Study the table carefully to answer the questions that follow.

What is the approximate average number of candidates appeared for the exam from Institute E over the years ?
- 1759
- 1586
- 1671
- 1924
- 1837
Correct

Average number of students appeared in examination from Institute E over the year

= $\frac{1530+1886+1806+1478+1654}{5}$

= $\frac{8354}{5}$

=1670.8 ≈ 1671 (Approx.)

Incorrect

Average number of students appeared in examination from Institute E over the year

= $\frac{1530+1886+1806+1478+1654}{5}$

= $\frac{8354}{5}$

=1670.8 ≈ 1671 (Approx.)
Question 48 of 50

48. Question
1 points
Study the table carefully to answer the questions that follow.

Percentage of candidates qualified over appeared from Institute D is the lowest during which of the following ?
- 2003
- 2004
- 2005
- 2007
- None of these
Correct

Percentage of successful studying in the year 2003

= $\frac{1567\times 100}{1765}$ = 88.78%

Percentage of successful studying in the year 2004

= $\frac{1024\times 100}{1574}$ = 65.05%

Percentage of successful studying in the year 2005

= $\frac{1210\times 100}{1754}$ = 68.99%

Percentage of successful studying in the year 2006

= $\frac{1145\times 100}{1364}$ = 83.94%

Percentage of successful studying in the year 2007

= $\frac{1214\times 100}{1510}$ = 80.40%

So, the minimum percentage of successful students was in the year 2004.

Incorrect

Percentage of successful studying in the year 2003

= $\frac{1567\times 100}{1765}$ = 88.78%

Percentage of successful studying in the year 2004

= $\frac{1024\times 100}{1574}$ = 65.05%

Percentage of successful studying in the year 2005

= $\frac{1210\times 100}{1754}$ = 68.99%

Percentage of successful studying in the year 2006

= $\frac{1145\times 100}{1364}$ = 83.94%

Percentage of successful studying in the year 2007

= $\frac{1214\times 100}{1510}$ = 80.40%

So, the minimum percentage of successful students was in the year 2004.
Question 49 of 50

49. Question
1 points
Study the table carefully to answer the questions that follow.

What is the percentage of the candidates qualified over the number of candidates appeared for exam in the year 2005 from all Institute together ? (rounded off to two digits after decimal)
- 92.34
- 73.47
- 66.94
- 83.59
- None of these
Correct

Number of students, appeared in the year 2005 from all institutes=1684+1550+1754+1806+1666= 8460

Number of successful candidates in 2005 from all institutes= 1500+1278+1210+1586+1498 =7072

Required percentage= $\frac{7072\times 100}{8460}$ =83.59

Incorrect

Number of students, appeared in the year 2005 from all institutes=1684+1550+1754+1806+1666= 8460

Number of successful candidates in 2005 from all institutes= 1500+1278+1210+1586+1498 =7072

Required percentage= $\frac{7072\times 100}{8460}$ =83.59
Question 50 of 50

50. Question
1 points
Study the table carefully to answer the questions that follow.

Approximately what is the percentage of candidates qualified over appeared from all the Institutes together in 2007 ?
- 68
- 55
- 74
- 92
- 86
Correct

Number of candidates in the year 2007 from all institutes = 1564+1575+1510+1654+1690= 7993

Number of successful in the year 2007 from all institutes= 1462+1388+1214+1296+1480= 6840

Required percentage= $\frac{6840\times 100}{7993}$ = 85.57 ≈ 86 (Approx.)

Incorrect

Number of candidates in the year 2007 from all institutes = 1564+1575+1510+1654+1690= 7993

Number of successful in the year 2007 from all institutes= 1462+1388+1214+1296+1480= 6840

Required percentage= $\frac{6840\times 100}{7993}$ = 85.57 ≈ 86 (Approx.)

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